满分代码:
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
using namespace std;
const int N=100;
int main(int argc, char** argv) {
int n;
cin>>n;
int B[N];
for(int i=0;i<n;i++){
cin>>B[i];
}
int sum1=B[0];//最大值
int sum2=B[0];//最小值
if(n==1){
cout<<sum1<<endl;
cout<<sum2<<endl;
}
else{
for(int i=1;i<n;i++){
sum1+=B[i];
if(B[i]!=B[i-1]){
sum2+=B[i];
}
}
cout<<sum1<<endl;
cout<<sum2<<endl;
}
return 0;
}