程序如下：

assume cs:code

data segment
	db 10 dup (0)
data ends

code segment
start:
	mov ax,12666
	mov bx,data
	mov ds,bx
	mov si,0
	
	call dtoc
	
	mov dh,8
	mov dl,3
	mov cl,2
	
	call show_str
	
	mov ax,4c00h
	int 21h
	
dtoc:
	push dx
	push cx
	push ax
	push si
	push bx
	
	mov bx,0;存放数值位数
	
s1:
	mov cx,10d
	mov dx,0
	
	div cx
	mov cx,ax
	
	jcxz s2
	
	add dx,30h;余数加30h得相应的ASCII码
	push dx;逐个保存
	
	inc bx;统计数值位数
	
	jmp short s1

s2:
	add dx,30h
	push dx
	inc bx	;最后一位cx未统计到(ax=cx=0，在s2再转换一次
	
	mov cx,bx;总共bx为进栈
	mov si,0

s3:
	pop ax 	;将入栈数值逐个输出
	
	mov [si],al ;根据要求 存放到di:[si]地址处
	inc si
	loop s3

okey:	
	pop bx
	pop si
	pop ax
	pop cx
	pop dx
	
	ret
	
show_str:
	push bx
	push cx
	push si
	
	mov al,0a0h
	
	dec dh
	mul dh
	
	mov bx,ax	
	mov al,2
	mul dl
	
	sub ax,2
	add bx,ax
	
	mov ax,0b800h
	mov es,ax
	
	mov di,0
	mov al,cl
	mov ch,0

s:
	mov cl,ds:[si]
	
	jcxz ok
	
	mov es:[bx+di],cl
	mov es:[bx+di+1],al
	
	inc si
	add di,2
	
	jmp short s

ok:	
	pop si
	pop cx
	pop bx
	
	ret

code ends
end start