#include <iostream>
#include <cstring>
#include <algorithm>
#include <cmath>
using namespace std;
int qmi(int a, int k) // 求a^k mod p
{
int res = 1 ;
while (k)
{
if (k & 1) res = (long long)res * a ;
a = (long long)a * a ;
k >>= 1;
}
return res;
}
int main()
{
int n;
while(cin>>n,n){
int t=n-1940;
t/=10;
double tt=qmi(2,t);
double ans=0;
for(int i=2;;i++){
ans+=log2(i);
if(ans>tt){
cout<<i-1<<endl;
break;
}
}
}
}
算法实践1.1 intel fastpone
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转载自blog.csdn.net/weixin_39057744/article/details/121106851
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