你的任务是为一个很受欢迎的银行设计一款程序,以自动化执行所有传入的交易(转账,存款和取款)。银行共有 n
个账户,编号从 1
到 n
。每个账号的初始余额存储在一个下标从 0 开始的整数数组 balance
中,其中第 (i + 1)
个账户的初始余额是 balance[i]
。
请你执行所有 有效的 交易。如果满足下面全部条件,则交易 有效 :
- 指定的账户数量在
1
和n
之间,且 - 取款或者转账需要的钱的总数 小于或者等于 账户余额。
实现 Bank
类:
Bank(long[] balance)
使用下标从 0 开始的整数数组balance
初始化该对象。boolean transfer(int account1, int account2, long money)
从编号为account1
的账户向编号为account2
的账户转帐money
美元。如果交易成功,返回true
,否则,返回false
。boolean deposit(int account, long money)
向编号为account
的账户存款money
美元。如果交易成功,返回true
;否则,返回false
。boolean withdraw(int account, long money)
从编号为account
的账户取款money
美元。如果交易成功,返回true
;否则,返回false
。
示例:
输入: ["Bank", "withdraw", "transfer", "deposit", "transfer", "withdraw"] [[[10, 100, 20, 50, 30]], [3, 10], [5, 1, 20], [5, 20], [3, 4, 15], [10, 50]] 输出: [null, true, true, true, false, false] 解释: Bank bank = new Bank([10, 100, 20, 50, 30]); bank.withdraw(3, 10); // 返回 true ,账户 3 的余额是 $20 ,所以可以取款 $10 。 // 账户 3 余额为 $20 - $10 = $10 。 bank.transfer(5, 1, 20); // 返回 true ,账户 5 的余额是 $30 ,所以可以转账 $20 。 // 账户 5 的余额为 $30 - $20 = $10 ,账户 1 的余额为 $10 + $20 = $30 。 bank.deposit(5, 20); // 返回 true ,可以向账户 5 存款 $20 。 // 账户 5 的余额为 $10 + $20 = $30 。 bank.transfer(3, 4, 15); // 返回 false ,账户 3 的当前余额是 $10 。 // 所以无法转账 $15 。 bank.withdraw(10, 50); // 返回 false ,交易无效,因为账户 10 并不存在。
提示:
n == balance.length
1 <= n, account, account1, account2 <= 105
0 <= balance[i], money <= 1012
transfer
,deposit
,withdraw
三个函数,每个 最多调用104
次
C++
class Bank {
public:
Bank(vector<long long>& balance) {
bank=balance;
}
bool transfer(int account1, int account2, long long money) {
if(account1<=bank.size() && account2<=bank.size() && bank[account1-1]>=money) {
bank[account1-1]-=money;
bank[account2-1]+=money;
return true;
}
return false;
}
bool deposit(int account, long long money) {
if(account<=bank.size()) {
bank[account-1]+=money;
return true;
}
return false;
}
bool withdraw(int account, long long money) {
if(account<=bank.size() && bank[account-1]>=money) {
bank[account-1]-=money;
return true;
}
return false;
}
private:
vector<long long> bank;
};
/**
* Your Bank object will be instantiated and called as such:
* Bank* obj = new Bank(balance);
* bool param_1 = obj->transfer(account1,account2,money);
* bool param_2 = obj->deposit(account,money);
* bool param_3 = obj->withdraw(account,money);
*/
java
class Bank {
private long[] bank;
public Bank(long[] balance) {
bank=balance;
}
public boolean transfer(int account1, int account2, long money) {
if(account1<=bank.length && account2<=bank.length && bank[account1-1]>=money) {
bank[account1-1]-=money;
bank[account2-1]+=money;
return true;
}
return false;
}
public boolean deposit(int account, long money) {
if(account<=bank.length) {
bank[account-1]+=money;
return true;
}
return false;
}
public boolean withdraw(int account, long money) {
if(account<=bank.length && bank[account-1]>=money) {
bank[account-1]-=money;
return true;
}
return false;
}
}
/**
* Your Bank object will be instantiated and called as such:
* Bank obj = new Bank(balance);
* boolean param_1 = obj.transfer(account1,account2,money);
* boolean param_2 = obj.deposit(account,money);
* boolean param_3 = obj.withdraw(account,money);
*/
python
class Bank:
def __init__(self, balance: List[int]):
self.bank = []
self.bank.extend(balance)
def transfer(self, account1: int, account2: int, money: int) -> bool:
if account1 <= len(self.bank) and account2 <= len(self.bank) and self.bank[account1 - 1] >= money:
self.bank[account1 - 1] -= money
self.bank[account2 - 1] += money
return True
return False
def deposit(self, account: int, money: int) -> bool:
if account <= len(self.bank):
self.bank[account - 1] += money
return True
return False
def withdraw(self, account: int, money: int) -> bool:
if account <= len(self.bank) and self.bank[account - 1] >= money:
self.bank[account - 1] -= money
return True
return False
# Your Bank object will be instantiated and called as such:
# obj = Bank(balance)
# param_1 = obj.transfer(account1,account2,money)
# param_2 = obj.deposit(account,money)
# param_3 = obj.withdraw(account,money)