需求描述
批量修改当前文件夹下所有的xml文件中的版本号字段,修改componentVersion字段对应的版本号内容
xml文件
aaa.xml
<?xml version="1.0" ?><CONTENT date="2021-12-09" version="1.0">
<Generate>11111</Generate>
<Info>
<Project>aaaaa</Project>
<componentVersion>1.0</componentVersion>
<Customer>CN</Customer>
</Info>
</CONTENT>
bbb.xml
<?xml version="1.0" ?><CONTENT date="2021-12-09" version="1.0">
<Generate>333333</Generate>
<Type>000</Type>
<Info>
<Project>ccccc</Project>
<componentVersion>1.0</componentVersion>
<Customer>CN</Customer>
</Info>
</CONTENT>
ccc.xml
<?xml version="1.0" ?><CONTENT date="2021-12-09" version="1.0">
<Generate>11111</Generate>
<Info>
<Project1>bbbbb</Project1>
<Project2>bbbbb</Project2>
<Project3>bbbbb</Project3>
<Project4>bbbbb</Project4>
<componentVersion>1.0</componentVersion>
<Customer>CN</Customer>
</Info>
</CONTENT>
python实现代码
test.py
#coding=utf-8
import sys
import xml.dom.minidom
import os
#获取传入的版本号,sys.argv[0]是python的文件名称
version=sys.argv[1]
print 'New version' +'='+version
for root,dirs, files in os.walk("./"):
print files #get current files
for sfile in files:
if os.path.splitext(sfile)[1] == '.xml': #只修改xml文件
#print sfile
#打开xml文档
dom = xml.dom.minidom.parse(sfile)
#得到文档元素对象
#root = dom.documentElement
componementVersion=dom.getElementsByTagName('componentVersion')
c1=componementVersion[0]
print ">---------------------<"
print sfile
print "Old Version:"+c1.firstChild.data
c1.firstChild.data=version
print "New Version:"+c1.firstChild.data
with open(os.path.join("./",sfile),'w') as fh: #write to xml file
dom.writexml(fh)
print ">----------end-----------<"
执行修改
root@virtual-machine:/home/test_old# python test.py 1.2
1.2
New version=1.2
['bbb.xml', 'aaa.xml', 'test.py', 'ccc.xml']
>---------------------<
bbb.xml
Old Version:1.0
New Version:1.2
>---------------------<
aaa.xml
Old Version:1.0
New Version:1.2
>---------------------<
ccc.xml
Old Version:1.0
New Version:1.2
>----------end-----------<
查看xml文件中所有componentVersion对应的版本号,实测已经修改