SELECT
*
FROM
SUPPLIER_USER a
WHERE
a.SUPPLIER_ID in (SELECT
SUPPLIER_ID
FROM
SUPPLIER_USER
GROUP BY
SUPPLIER_ID
HAVING
count(*) > 1
)
and
a.SUPPLIER_ID = 1862
查找表中某字段存在值相同的纪录
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转载自z3sm2012.iteye.com/blog/1574042
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