<?xml version="1.0" encoding="UTF-8" ?>
<result>
<lrc id="189296" artist="陶晶莹" title="太委屈"></lrc>
<lrc id="1243" artist="xxx" title="vvv"></lrc>
</result>
如何查出中间两行,并给值到一个数组里 id[],artist[]和title[]里?
最后要列出来。并在以后使用这些变量。
本人实在很菜啊。目前只摸索出 cat a.xml | grep '</lrc>'
-_-! ...........差很远啊
solution 1:
#!/bin/bash
declare -a ids
declare -a artists
declare -a titles
tmp=`sed -n -e 's/<lrc //' -e 's/><\/lrc>//p' $1 | sed -e 's/id="//' -e 's/artist="//' -e 's/title="//' -e 's/"//g'`
lrc=($(echo $tmp))
for((i=0, j=0; i<${#lrc
#echo "${lrc[i]}--${lrc[++i]}--${lrc[++i]}"
ids[j]=${lrc[i]}
artists[j]=${lrc[++i]}
titles[j]=${lrc[++i]}
done
for((k=0; k<${#ids
echo "id: ${ids[k]}--artist: ${artists[k]}--title: ${titles[k]}"
done
将以上代码保存为xmlparser.sh
代码:
<?xml version="1.0" encoding="UTF-8" ?>
<result>
<lrc id="189296" artist="陶晶莹" title="太委屈"></lrc>
<lrc id="1243" artist="xxx" title="vvv"></lrc>
</result>
将以上代码保存为test.xml
然后在终端执行
引用:
./xmlparser.sh test.xml
结果如下:
引用:
ranfow@ranfow-laptop:~/codes/sh$ ./xmlparser.sh test.xml
id: 189296--artist: 陶晶莹--title: 太委屈
id: 1243--artist: xxx--title: vvv
solution 2:
cat a.xml | grep '</lrc>'|sed "s/<lrc //;s/><\/lrc>//;s/id=/id[NUM]=/;s/artist=/artist[NUM]=/;s/title=/title[NUM]=/;s/\"\ /\";/g"|while read line;do
echo "${line//NUM/${i:-0}}"
((i++))
done >/tmp/source
. /tmp/source
rm /tmp/source
for((j=0; j<${#id[@]}; j++));do
echo -e "id[$j]: ${id[j]}\nartist[$j]: ${artist[j]}\ntitle[$j]: ${title[j]}"
done
不过有临时文件不爽。。。。
solution 3:
cat a.xml | grep '</lrc>'|sed "s/<lrc //;s/><\/lrc>//;s/=/[NUM]=/g;s/\"\ /\";/g"|while read line;do
echo "${line//NUM/${i:-0}}"
((i++))
done >/tmp/source
. /tmp/source
rm /tmp/source
for((j=0; j<${#id[@]}; j++));do
echo -e "id[$j]: ${id[j]}\nartist[$j]: ${artist[j]}\ntitle[$j]: ${title[j]}"
done