CREATE FUNCTION f_getIdNum(inStr VARCHAR(255)) RETURNS VARCHAR(255) LANGUAGE SQL BEGIN ATOMIC DECLARE outStr VARCHAR(255) DEFAULT ''; DECLARE k INT DEFAULT 1; ----判断是否存在全角字符,存在则进行剔除 if(length(inStr) != length(inStr, CODEUNITS32)) then WHILE(k<=length(inStr)) do if(ascii(substr(inStr,k,1))< 128) then set outStr = outStr || substr(inStr,k,1); end if; set k = k+1; END WHILE; ELSE SET outStr = outStr || inStr; end if; RETURN outStr; END;
db2 去除全角字符
最近在做报表,需求中要求把一字段剔除全角字符然后做相似检查,再网上搜了好多关于db2判断是否全角字符的例子,然后写了下面一函数,还好使,不知道有没有bug存在,贴出来,望大牛指正........
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转载自deer.iteye.com/blog/1439436
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