// 又是一道交不上的题 ... 大写的无语
#include<bits/stdc++.h>
using namespace std;
int main()
{
string s;
int n,cnt,i,b,re;
while( cin>>n )
{
for( cnt=1;cnt<=n;cnt++ )
{
cin>>s>>b; b=abs(b);
i=re=0; if( s[i]=='-' ) i++;
for( ;i<s.size();i++ )
{
re=re*10+( s[i]-'0' );
re%=b;
}
cout<<"Case "<<cnt<<": ";
if( re ) cout<<"not ";
cout<<"divisible"<<endl;
}
}
return 0;
}
not _ Large Division _ 模拟
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转载自blog.csdn.net/qq_63173957/article/details/124476102
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