js_Ipv4以及ipv4段正则校验

js_Ipv4以及ipv4段正则校验

他们都是在支持IPv4的情况下增加的格外校验
只校验ipv4去掉(/\d+)?即可
?:?前面的key出现0次或者

let ipCheck = /^(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])$/ 

1.ip+/+多位数字

let ipCheck = /^(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])(\/\d+)?$/ 

2.ip+/+1-2位数字

let aaa2 = /^(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])(\/\d{1,2})?$/

在这里插入图片描述
3.校验ip+/+1-32

let zjq9 = /^(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])(\/(?:[1-9]|[12][0-9]|3[012]))?$/ 

在这里插入图片描述

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转载自blog.csdn.net/qq_43291759/article/details/125335917