此题应该是本场比赛的签到题,一道究极无敌模拟题。
做出这道题需要拥有以下前置知识点:
1、闰年能被4整除,但是不能被100整除,或者能被400整除。
2、1~12月各有多少天,闰年2月有29天。
AC代码
#include <bits/stdc++.h>
using namespace std;
string s;
int first,second,third;
int md[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int rnmd[13]={0,31,29,31,30,31,30,31,31,30,31,30,31};
bool rn(int year){
return ((year%4==0 and year%100!=0) or year%400==0);
}
bool MMDDYY(int year,int month,int day){
if(rn(year)){//是闰年
if(month>=1 and month<=12 and day>=1 and day<=rnmd[month] and year>=0 and year<=99)return true;
}else{
if(month>=1 and month<=12 and day>=1 and day<=md[month] and year>=0 and year<=99)return true;
}
return false;
}
bool DDMMYY(int year,int month,int day){
if(rn(year)){//是闰年
if(month>=1 and month<=12 and day>=1 and day<=rnmd[month] and year>=0 and year<=99)return true;
}else{
if(month>=1 and month<=12 and day>=1 and day<=md[month] and year>=0 and year<=99)return true;
}
return false;
}
int main(){
ios::sync_with_stdio(false);
cin.tie(nullptr),cout.tie(nullptr);
cin>>s;
first=(s[0]-'0')*10+(s[1]-'0');
second=(s[3]-'0')*10+(s[4]-'0');
third=(s[6]-'0')*10+(s[7]-'0');
if(MMDDYY(third,first,second) and DDMMYY(third,second,first)){
cout<<"BOTH";
return 0;
}
if(MMDDYY(third,first,second)){
cout<<"MMDDYY";
return 0;
}
if(DDMMYY(third,second,first)){
cout<<"DDMMYY";
return 0;
}
cout<<"NOTHING";
return 0;
}