输入年份和天数,输出对应的年、月、日

例:输入格式:2000 61
       输出格式:2000-3-1    即2000年的第61天是3月1日 

//使用指针作为函数参数返回多个函数值

#include <stdio.h>
void month_day(int year,int yearday,int *pmonth,int *pday){
	int k,leap;
	int tab[2][13]={
		{0,31,28,31,30,31,30,31,31,30,31,30,31},
		{0,31,29,31,30,31,30,31,31,30,31,30,31},
	};                                       //定义数组存放闰年和非闰年每个月的天数
	leap=(year%4==0&&year%100!=0)||year%400==0;   //闰年判别条件
	for(k=1;yearday>tab[leap][k];k++)
		yearday-=tab[leap][k];
		*pmonth=k;
		*pday=yearday;
	
} 
int main(){
	int day,month,yearday,year;             //定义代表日、月、年和天数的变量
	printf("input year and yearday:");
	scanf("%d%d",&year,&yearday);
	month_day(year,yearday,&month,&day);
	printf("%d-%d-%d",year,month,day);
	
	return 0;
}

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转载自blog.csdn.net/MissLemonh/article/details/82873958