1、减少if…else面条代码

const getPrice = (name) => {
    
    
	if (name === 'hamburger') {
    
    
		return 20
	} else if (name === 'French fries') {
    
    
		return 15
	} else if (name === 'ice cream') {
    
    
		return 5
	}
}
console.log(getPrice('hamburger')) // 20

优化：

const foodMap = {
    
    
	'hamburger' : 20,
	'French fries' : 15,
	'ice cream' : 5,
	'Coffee' : 12
}
const getPrice = (name) => {
    
    
	return foodMap[name]
}
console.log(getPrice('hamburger')) // 20

2、管道操作取代冗余循环

const foods = [{
    
    
	name: 'hamburger',
	group: 1
}, {
    
    
	name: 'French fries',
	group: 1
}, {
    
    
	name: 'Coffee',
	group: 2
}, {
    
    
	name: 'ice cream',
	group: 1
}]

找出属于套餐1的食物，先对数组过滤再重组

const names = foods
	.filter( i => i.group === 1 )
	.map( i => i.name )
console.log(names) // ['hamburger', 'French fries', 'ice cream']

3、find取代冗余循环

食品对象数组中按照属性值查找特定的食物

const hamburger = foods
	.find( i => i.name === 'hamburger' && i.group === 1)
console.log(hamburger) // {name: 'hamburger', group: 1}

4、includes取代冗余循环

一碗「康某傅老坛酸菜牛肉面」有「酸菜」，「面」，「牛肉粒」，「烟头」和「脚皮」组成，那我们想用函数证实这个面里面是否有脚皮

const sauerkrautBeefNoodles = ['a' , 'b' , 'c' , 'd']
const hasD = sauerkrautBeefNoodles.includes('d')
console.log(hasD) // true

5、result返回值

const getUrl = (content, prefix, suffix) => {
    
    
	let result = content
	if (prefix) {
    
    
		result = `${
      
      prefix}${
      
      result}`
	}
	if (suffix) {
    
    
		result = `${
      
      result}${
      
      suffix}`
	}
	return result
}
console.log(getUrl('www.apifox', 'https://', '.cn')) // https://www.apifox.cn

6、提前返回

const activeParentKeys = (selectKeys) => {
    
    
	if (!selectKeys) return []
	if (selectKeys !== 'key1') {
    
    
		return getParentKeys(selectKeys)
	}
	return []
}

7、保持对象完整

解构完整对象

const getDocDetail = (data) => {
    
    
	const {
    
    icon, content}
	console.log(icon)
	console.log(content)
}
getDocDetail(data)

8、巧用运算符

let activeKey = selectedKey || ''