//求和:1+2-3+4-...n var sum2 = function(n) { var s1 = 1; var s2 = 0; if(n > 1){ for (var i = 1; i < n; i++) { if (i%2 === 0) { var s1 = s1 - (i + 1); //s1 = 1,开始 } else { var s2 = s2 + (i + 1); } } var s = s1 + s2; return s; }else{ return 1; } } console.log(sum2(n));
JS求和方法
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转载自www.cnblogs.com/hezhouhang/p/9143256.html
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