csp 2022.12-3 JPEG 解码 题解,采取了比较另类的输入方式

题目链接

http://118.190.20.162/view.page?gpid=T158

代码

#include <bits/stdc++.h>
using namespace std;

const int SIZE = 1e3 + 10;
const double PI = acos(-1);
int n, t;
int quantization[8][8] = {
    
     0 }, m[8][8] = {
    
     0 };
void print() {
    
    
	for (int i = 0; i < 8; i++) {
    
    
		for (int j = 0; j < 8; j++) {
    
    
			cout << m[i][j] << " ";
		}
		cout << endl;
	}
}
void quantity() {
    
    
	for (int i = 0; i < 8; i++) {
    
    
		for (int j = 0; j < 8; j++) {
    
    
			m[i][j] *= quantization[i][j];
		}
	}
}
void scan() {
    
    
	if (n) {
    
    
		int direction = 0,//0代表,1代表
			i = 7, j = 0, //下一个坐标(以矩阵左下角为原点,这个是我一开始这么写的,后面懒得改了)
			change = -1;//指定哪个k要变方向
		for (int k = 0; k < n; k++) {
    
    
			cin >> m[i][j];
			if (i == 7
				&& change != k) {
    
    //没有指定就不↓或→移动
				change = k + 1;//指定下一个才移动
				direction = 0;
				j++;//最顶端向右→移
			}
			else if (j == 0
				&&i!=0 //避免原点的下一个输入出错
				&& change != k) {
    
    
				change = k + 1;
				direction = 1;
				i--;//最左端向下↓移
			}
			else if (i == 0
				&&j!=1 //避免在(0,0)点向右移动后在(0,1)点继续向右移动
				&& change != k) {
    
    
				change = k + 1;//指定下一个才移动
				direction = 1;
				j++;//最底端向右→移
			}
			else if (j == 7&&i!=7 && change != k) {
    
    
				change = k + 1;
				direction = 0;
				i--;//最右端向下↓移
			}
			else {
    
    
				if (direction) {
    
    
					i++;//↑→
					j++;
				}
				else {
    
    
					i--;//↓←
					j--;
				}
			}
		}
		//转换为以矩阵左上角为原点
		for (int i = 7; i >= 4; i--) {
    
    
			for (int j = 0; j < 8; j++) {
    
    
				int t = m[i][j];
				m[i][j] = m[7 - i][j];
				m[7 - i][j] = t;
			}
		}
	}
}
double alpha(int x) {
    
    
	if (x == 0) {
    
    
		return sqrt(0.5);
	}
	return 1;
}
void reverseChange() {
    
    
	double temp[8][8] = {
    
     0 };
	for (int i = 0; i < 8; i++) {
    
    
		for (int j = 0; j < 8; j++) {
    
    
			for (int u = 0; u < 8; u++) {
    
    
				for (int v = 0; v < 8; v++) {
    
    
					temp[i][j] += (0.25 * alpha(u) * alpha(v) * m[u][v] * cos(0.125 * PI * (i + 0.5) * u) * cos(0.125 * PI * (j + 0.5) * v));
				}
			}
		}
	}
	//特别注意!!!m矩阵要算完才能改
	for (int i = 0; i < 8; i++) {
    
    
		for (int j = 0; j < 8; j++) {
    
    
			m[i][j] = (int)(temp[i][j] + 128 + 0.5);//四舍五入
			if (m[i][j] > 255) {
    
    
				m[i][j] = 255;
			}
			else if (m[i][j] < 0) {
    
    
				m[i][j] = 0;
			}
		}
	}
}
int main()
{
    
    
	for (int i = 0; i < 8; i++) {
    
    
		for (int j = 0; j < 8; j++) {
    
    
			cin >> quantization[i][j];
		}
	}
	cin >> n >> t;

	switch (t) {
    
    
	case 1:
		scan();
		quantity();
		break;
	case 2:
		scan();
		quantity();
		reverseChange();
		break;
	default:
		scan();
		break;
	}
	print();
	return 0;
}

总结

建议还是用数组指定输入顺序来读入,这个输入的方式也是debug很多次才写对的。

猜你喜欢

转载自blog.csdn.net/qq_33843237/article/details/129350379