Boudreaux and Thibodeaux are on the road again …
“Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!”
“Don’t worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!”
“We’re not going to make it, I say!”
So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?
Input
Input to this problem will consist of a single data set. The data set will be formatted according to the following description.
The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.
Output
There will be exactly one line of output. This line will be:
NO CRASH
if the height of the 18-wheeler is less than the height of each of the underpasses, or:
CRASH X
otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.
Sample Input
180 160 170
Sample Output
CRASH 160

无敌大水题

代码：

#include <cstdio>
#include <algorithm>
using namespace std;
int main(void){
    int a,b,c;
    scanf("%d%d%d",&a,&b,&c);
    if(a>168 && b>168 && c>168){
        printf("NO CRASH\n");
    }
    else if(a<=168){
        printf("CRASH %d\n",a);
    }
    else if(b<=168){
        printf("CRASH %d\n",b);
    }
    else if(c<=168){
        printf("CRASH %d\n",c);
    }
    return 0;
}