测试:
public static void main(String[] args) {
Date date = new Date();
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String endTime = simpleDateFormat.format(date);
try{
long i=getTimeDifference("2022-12-05 12:00:00",endTime);
if(i<10) {
System.out.println("维修时间为" + i + "分钟!,需超过10分钟!");
}else {
System.out.println("维修完成");
}
}catch(Exception e) {
e.printStackTrace();
}
工具类:
public static long getTimeDifference(String oldTime,String newTime) throws ParseException {
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
long NTime =df.parse(newTime).getTime();
//从对象中拿到时间
long OTime = df.parse(oldTime).getTime();
long diff=(NTime-OTime)/1000/60;
return diff;
}
结果
public static void main(String[] args) throws ParseException {
//十位数时间戳
long start = 1611298952;
long end = 1611299007;
long diffSeconds = end - start;
Double minute = new BigDecimal((float) diffSeconds / 60).setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
Double hour = new BigDecimal((float) diffSeconds / (60 * 60)).setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
//时间戳为13位时
//Double minute = new BigDecimal((float) diffSeconds / (1000 * 60)).setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
//Double hour = new BigDecimal((float) diffSeconds / (1000 * 60 * 60)).setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
System.out.println(minute); //打印结果:0.92
System.out.println(hour); //打印结果:0.02
}