SELECT
university,
AVG(question_cnt) AS avg_question_cnt
FROM
user_profile
GROUP BY
university
ORDER BY
avg_question_cnt
执行顺序
where 、group by 、count / avg、having、order by 、limit
SQL20 分组排序练习题
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转载自blog.csdn.net/QinLaoDeMaChu/article/details/127430728
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