在三乘三的方格中,当"X"或者"O"有一个在纵向/横向/交叉处有三个连成一条线,就可视为成功,下面设置的是"X"先走:
public static void main(String[] args) {
System.out.println("井字游戏:" + validBoard(new String[]{"XXX", "OXO", "O O"}));
}
private static boolean validBoard(String[] strings) {
int xCount = 0, oCount = 0;
for (int i = 0; i < strings.length; i++) {
for (char c:strings[i].toCharArray()) {
if (c == 'X') {
xCount++;
}
if (c == 'O') {
oCount++;
}
}
}
if (xCount != oCount && xCount - oCount != 1) {
return false;
}
if (win(strings, "XXX") && xCount-oCount != 1) {
return false;
}
if (win(strings, "OOO") && xCount != oCount) {
return false;
}
return true;
}
private static boolean win(String[] strings, String str) {
for (int i = 0; i < strings.length; i++) {
if (str.equals("" + strings[0].charAt(i) + strings[1].charAt(i)+strings[2].charAt(i))) {
return true;
}
if (str.equals(strings[i])) {
return true;
}
}
if (str.equals("" + strings[0].charAt(0) + strings[1].charAt(1) + strings[2].charAt(2))) {
return true;
}
if (str.equals("" + strings[0].charAt(2) + strings[1].charAt(1) + strings[2].charAt(0))) {
return true;
}
return false;
}