python 3实现从txt文件读取,把列表(List)中字符串转整数,并用逗号分开

最近科研遇到这样一个需求:把list里的字符串转化为整数:

例如:

list=['1','2','3','4','5']

转化为:

list=[1,2,3,4,5]

在产生200位bit的随机二进制秘钥,这些秘钥都是保存在txt格式的文本中的,文本中的数据格式如下所示:



我现在需要把这些秘钥都读取出来,并且每个秘钥的后面要用逗号隔开,

bits=[1,1,0,1,0,0,1,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,1,0,1,1,0,1,0,1,0,1,1,0,1,
1,1,0,1,0,0,0,0,1,0,1,1,1,1,0,0,0,0,1,0,1,0,1,1,0,1,1,1,0,0,0,0,1,0,1,0,1,1,
1,0,0,1,1,1,1,1,1,0,1,1,1,1,0,1,1,0,0,0,0,0,0,1,1,1,1,1,1,0,1,1,1,1,1,0,0,1,
1,1,1,1,1,1,1,1,1,0,0,0,1,0,0,0,0,0,1,1,1,0,1,0,0,1,0,0,0,0,1,1,1,1,0,0,1,1,
1,0,0,0,1,0,1,1,0,0,0,0,0,1,0,0,0,1,1,1,1,0,1,0,1,1,0,0,0,1,0,0,1,1,1,0,0,1,
1,1,0,0,1,0,1,1,1,1,0,1,1,1,0,0,0,1,1,0,1,1,1,0,1,1,0,1,0,0,1,1,1,1,1,1,1,1,
1,1,0,0,1,0,0,0,1,1,1,1,0,1,1,0,0,1,0,0,1,1,1,1,0,1,1,1,0,0,1,0,1,0,1,1,1,0,
0,0,1,0,0,1,1,0,0,1,1,1,0,0,1,0,1,0,1,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,
1,0,0,0,0,0,1,1,1,1,1,1,1,0,0,1,0,1,1,0,0,0,1,1,1,1,0,1,0,1,1,0,0,1,1,1,1,1,
0,1,1,0,1,0,1,0,1,1,1,0,1,0,0,1,1,0,1,1,1,1,1,0,0,1,1,0,1,1,0,0,1,1,1,1,0,0,1,0]

然后用python来处理这些数据 ,所以现在问题就在于怎么把数据从txt文件中读取出来,然后保存成上面这个样子。

发现一个问题,就是直接使用file.readlines()这个方法读取出来的不是自己想要的结果:如下:

file = open('D:\\123.txt')
lines = file.readlines()
print(lines) 

上面代码执行结果如下:显然不是我想要的


看上面的代码,我们发现有下面几个问题:

①包含字符串' '

②最后多了一个\n

那么就要解决掉这些问题: 代码如下

#读取文件
file = open('D:\\123.txt')
lines = file.readlines()
# print(lines) 
strr=''.join(lines)

bits=[]
for line in strr:
    for ind in line:
        # ts=int(ind)
        bits.append(ind)       
bits.remove('\n')  
for index,item in enumerate(bits):
    bits[index]=eval(item)

print(bits) 

执行结果如下:


达到了自己想要的结果。





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转载自blog.csdn.net/zhaomengszu/article/details/80566296