代码如下:
# include <stdio.h>
# include < math.h>
int main()
{
int year=0;
int leap=0;
scanf_s("%d\0",&year);
if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0)//此处用一个逻辑表达式包含所有的闰年条件,在所有方法中最为简单直观
leap = 1;
else leap =0;
if (leap == 1)
printf("是");
else printf("否");
return 0;
}
附上编译结果:
编译器用的是 vs code 2022,各位观众老爷麻烦点个赞再走,小女子在此谢过