Binary Tree Preorder Travers

Given a binary tree, return the preorder traversal of its nodes' values.

Example:

Input: [1,null,2,3]
   1
    \
     2
    /
   3

Output: [1,2,3]

Follow up: Recursive solution is trivial, could you do it iteratively?

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    vector<int> preorderTraversal(TreeNode* root) {
        stack<TreeNode*> s;
        vector<int> ret;
        TreeNode *p=root;
        while(p||!s.empty())
        {
            while(p)
            {
                s.push(p);
                ret.push_back(p->val);
                p=p->left;
            }
            if(!s.empty())
            {
                p=s.top();
                s.pop();
                p=p->right;
            }
        }
        return ret;
    }
};

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转载自blog.csdn.net/zrh_csdn/article/details/80849819