C/C++ 判断五个整形的最大值和最小值(用三目运算符实现)

int Xmax(int a,int b,int c, int d, int e)
{
    int max;
    max=(a>b?a:b)>c?(a>b?a:b):c;
    max=(max>d?max:d)>e?(max>d?max:d):e;
    return max;
}

int Xmin(int a,int b,int c, int d, int e)
{
    int min;
    min=(a<b?a:b)<c?(a<b?a:b):c;
    min=(min<d?min:d)<e?(min<d?min:d):e;
    return min;
}

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转载自blog.csdn.net/Dennis_Sck/article/details/80865650