leetcode +字母到数字的26进制

点击打开链接
class Solution {
public:
    int titleToNumber(string s) {
        int res=0;
        for(int i=0; i<s.length();i++){
            res = res*26;
            res += s[i]-'A'+1;
        }
        return res;
    }
};

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转载自blog.csdn.net/u013554860/article/details/80922673