计算相邻两行的年龄的差距
表中的数据如下
select (s.age-(select age from stu where id - s.id = 1)) from stu as s;
select a.age-b.age from stu a,stu b where a.id-b.id=1;
select a.age-b.age from stu a inner join stu b on a.id = b.id + 1;
计算相邻两行的年龄的差距
表中的数据如下
select (s.age-(select age from stu where id - s.id = 1)) from stu as s;
select a.age-b.age from stu a,stu b where a.id-b.id=1;
select a.age-b.age from stu a inner join stu b on a.id = b.id + 1;