剑指offer第25题:合并两个排序的链表

题目描述

输入两个单调递增的链表,输出两个链表合成后的链表,当然我们需要合成后的链表满足单调不减规则。

# -*- coding:utf-8 -*-
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
class Solution:
    # 返回合并后列表
        def Merge(self, pHead1, pHead2):
            # write code here
            if pHead1 == None:
                return pHead2
            if pHead2 == None:
                return pHead1
            if pHead1.val >= pHead2.val:
                merge = pHead2
                merge.next = self.Merge(pHead1, pHead2.next)
            else:
                merge = pHead1
                merge.next = self.Merge(pHead1.next, pHead2)
            return merge   
 
 

利用递归的方法,给两个链表排序。

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转载自blog.csdn.net/zhangjiaxuu/article/details/80915264