%.2f自动四舍五入怎么破?

#include <stdio.h>
int main()
{
    double n=21.195;
    printf("%.2f\n",n);
    return 0;
}

结果:21.20

#include <stdio.h>
int main()
{
    double n=21.195;
    n*=100;//2119.5
    n=(int)n;//2119
    n=n/100;//21.19
    printf("%.2f\n",n);
    return 0;
}

结果:21.19
简化一下代码:

#include <stdio.h>
int main()
{
    double n=21.195;
    n=(double)(int)(100*n)/100;
    printf("%.2f\n",n);
    return 0;
}

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转载自blog.csdn.net/ac__go/article/details/78380413