/** * 判断字符串是否是全数字 * @param str * @return */ public static boolean isInteger(String str) { Pattern pattern = Pattern.compile("^[-\\+]?[\\d]*$"); return pattern.matcher(str).matches(); } public static boolean isNumeric(String str){ for (int i = str.length();--i>=0;){ if (!Character.isDigit(str.charAt(i))){ return false; } } return true; } private static boolean issNumeric(String str) { Pattern pattern = Pattern.compile("[0-9]*"); Matcher isNum = pattern.matcher(str); if (isNum.matches()) { return true; } else { return false; } } public static boolean isDate(String strDate) { Pattern pattern = Pattern .compile("^((\\d{2}(([02468][048])|([13579][26]))[\\-\\/\\s]?((((0?[13578])|(1[02]))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])))))|(\\d{2}(([02468][1235679])|([13579][01345789]))[\\-\\/\\s]?((((0?[13578])|(1[02]))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\\-\\/\\s]?((0?[1-9])|(1[0-9])|(2[0-8]))))))(\\s(((0?[0-9])|([1-2][0-3]))\\:([0-5]?[0-9])((\\s)|(\\:([0-5]?[0-9])))))?$"); Matcher m = pattern.matcher(strDate); if (m.matches()) { return true; } else { return false; } }
java判断字符串能否转化为整型和日期型
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转载自blog.csdn.net/qingfengmuzhu1993/article/details/80430393
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