双击返回



//在Activity下面写


private long mExitTime;

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {

    if (keyCode == KeyEvent.KEYCODE_BACK && event.getRepeatCount() == 0) {

        exit();
        return true;
    }
    return super.onKeyDown(keyCode, event);
}

public void exit() {
    if ((System.currentTimeMillis() - mExitTime) > 2000) {
        Toast.makeText(MainActivity.this, "再按一次退出", Toast.LENGTH_SHORT).show();
        mExitTime = System.currentTimeMillis();
    } else {

        finish();
        System.exit(0);
    }
}

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转载自blog.csdn.net/qq_42120002/article/details/80969861