【每日一题Leetcode】104. Maximum Depth of Binary Tree

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Note: A leaf is a node with no children.

Example:

Given binary tree [3,9,20,null,null,15,7],

    3
   / \
  9  20
    /  \
   15   7

return its depth = 3.


思路:这个题的重点是返回最大深度。递归方法检查每个node是否存在,如果存在进一步检查node.left和node.right,返回最大的一个。

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution:
    def maxDepth(self, root):
        """
        :type root: TreeNode
        :rtype: int
        """

        if root == None:
            return 0
        else:
            return 1 + max(self.maxDepth(root.left),self.maxDepth(root.right))
         
        
 
        return 

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转载自blog.csdn.net/github_39395521/article/details/80883077