更多可以参考:http://blog.csdn.net/fn_2015/article/details/54286366 下面是我自己写的sql 相同分数的名次相同的情况 : SELECT t.*, ( SELECT count(*) + 1 FROM ( SELECT t1.score FROM t_student_score t1 WHERE 1 = 1 GROUP BY t1.score ) t2 WHERE t2.score > t.score ) AS rank FROM t_student_score t WHERE 1 = 1 ORDER BY t.score desc LIMIT 20
mysql根据分数排名次sql语句
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转载自sky-xin.iteye.com/blog/2378403
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