python 学习 随机密码生成 重复元素判定1、2 DAY18

随机密码

import random
ls = []
for i in range(26):
    n = 97
    n += i
    ls.append(chr(n))

for i in range(26):
    n = 65
    n += i
    ls.append(chr(n))

for i in range(9):
    n = 49
    n += i
    ls.append(chr(n))
for j in range(10):
    for i in range(8):
        n = random.choice(ls)
        print(n,end = '')
    print()

重复元素判定1

def jug(ls):
    for i in range(1,len(ls)):
        for j in range(i):
            if ls[i] == ls[j]:
                return True
    return "无重复!"

s = [1,2,4,5,6,66,'a','f','d',]
print(jug(s))
 

2

s = [1,2,4,5,6,66,'a','f','d',1]
n = set(s)
if len(s) == len(n):
    print("无重复!")
else:
    print("有重复!")

猜你喜欢

转载自blog.csdn.net/u011451186/article/details/81105265