测试多边形与圆相交面积模板
#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstdlib>
using namespace std;
const double eps = 1e-8;
const double PI = acos(-1.0);
int dcmp(double x){
if( x > eps ) return 1;
return x < -eps ? -1 : 0;
}
struct Point{
double x,y;
Point(){
x = y = 0;
}
Point(double a,double b){
x = a;y = b;
}
inline void input(){
scanf("%lf%lf",&x,&y);
}
inline Point operator-(const Point &b)const{
return Point(x - b.x,y - b.y);
}
inline Point operator+(const Point &b)const{
return Point(x + b.x,y + b.y);
}
inline Point operator*(const double &b)const{
return Point(x * b,y * b);
}
inline double dot(const Point &b)const{
return x * b.x + y * b.y;
}
inline double cross(const Point &b,const Point &c)const{
return (b.x - x) * (c.y - y) - (c.x - x) * (b.y - y);
}
inline double Dis(const Point &b)const{
return sqrt((*this-b).dot(*this-b));
}
inline bool InLine(const Point &b,const Point &c)const{ //三点共线
return !dcmp(cross(b,c));
}
inline bool OnSeg(const Point &b,const Point &c)const{ //点在线段上,包括端点
return InLine(b,c) && (*this - c).dot(*this - b) < eps;
}
};
inline double min(double a,double b){
return a < b ? a : b;
}
inline double max(double a,double b){
return a > b ? a : b;
}
inline double Sqr(double x){
return x * x;
}
inline double Sqr(const Point &p){
return p.dot(p);
}
Point LineCross(const Point &a,const Point &b,const Point &c,const Point &d){
double u = a.cross(b,c) , v = b.cross(a,d);
return Point((c.x * v + d.x * u) / (u + v) , (c.y * v + d.y * u) / (u + v));
}
double LineCrossCircle(const Point &a,const Point &b,const Point &r,
double R,Point &p1,Point & p2){
Point fp = LineCross(r , Point(r.x+a.y-b.y , r.y+b.x-a.x) , a , b);
double rtol = r.Dis(fp);
double rtos = fp.OnSeg(a , b) ? rtol : min(r.Dis(a) , r.Dis(b));
double atob = a.Dis(b);
double fptoe = sqrt(R * R - rtol * rtol) / atob;
if( rtos > R - eps ) return rtos;
p1 = fp + (a - b) * fptoe;
p2 = fp + (b - a) * fptoe;
return rtos;
}
double SectorArea(const Point &r,const Point &a,const Point &b,double R){ //不大于180度扇形面积,r->a->b逆时针
double A2 = Sqr(r - a) , B2 = Sqr(r - b) , C2 = Sqr(a - b);
return R * R * acos( (A2 + B2 - C2) * 0.5 / sqrt(A2) / sqrt(B2)) * 0.5;
}
double TACIA(const Point &r,const Point &a,const Point &b,double R){
double adis = r.Dis(a) , bdis = r.Dis(b);
if( adis < R + eps && bdis < R + eps )
return r.cross(a , b) * 0.5;
Point ta , tb;
if( r.InLine(a,b) ) return 0.0;
double rtos = LineCrossCircle(a, b, r, R, ta, tb);
if( rtos > R - eps )
return SectorArea(r, a, b, R);
if( adis < R + eps )
return r.cross(a, tb) * 0.5 + SectorArea(r, tb, b, R);
if( bdis < R + eps )
return r.cross(ta, b) * 0.5 + SectorArea(r, a, ta, R);
return r.cross(ta, tb) * 0.5 + SectorArea(r, tb, b, R) + SectorArea(r, a, ta, R);
}
const int MAXN = 505;
Point p[MAXN];
double SPICA(int n,Point r,double R){
int i;
double ret = 0 , if_clock_t;
for( i = 0 ; i < n ; ++i ){
if_clock_t = dcmp(r.cross(p[i], p[(i + 1) % n]));
if( if_clock_t < 0 )
ret -= TACIA(r, p[(i + 1) % n], p[i], R);
else ret += TACIA(r, p[i], p[(i + 1) % n], R);
}
return fabs(ret);
}
int main(){
int n,i;
double k;
int cont=1;
while(scanf("%d %lf",&n,&k)!=EOF)
{
for( i = 0 ; i < n ; ++i ) //顶点坐标
p[i].input();
Point A,B;
A.input();
B.input();
double D = (2.0*k*k*A.x-2.0*B.x)/(1.0-k*k);
double E = (2.0*k*k*A.y-2.0*B.y)/(1.0-k*k);
double F = (B.x*B.x+B.y*B.y-k*k*(A.x*A.x+A.y*A.y))/(1.0-k*k);
Point circle;
circle.x=(-D/2.0);
circle.y=(-E/2.0);
double ans=SPICA(n,circle,sqrt(D*D+E*E-4*F)/2.0);
printf("Case %d: %.10lf\n",cont++,ans);
}
return 0;
}