最简单的方法是在配置文件中设置，利用配置文件中的order-by 属性来处理
-
<hibernate-mapping> -
<class name="com.adcourse.form.Topics" table="tb_topics"> -
<id name="id" column="id" type="int"> -
<generator class="increment"/> -
</id> -
<set name="reply" order-by="datetime asc" inverse="true" cascade="all" lazy="false" > -
<key column="topics_id"></key> -
<one-to-many class="com.adcourse.form.Reply"/> -
</set> -
</class> -
</hibernate-mapping> -
<hibernate-mapping> -
<class name="com.adcourse.form.Reply" table="tb_reply"> -
<id name="id" column="id" type="int"> -
<generator class="increment"/> -
</id> -
<property name="rdatetime" column="datetime" type="java.util.Date" not-null="true"/> -
<many-to-one name="topic" column="topics_id" class="com.adcourse.form.Topics" /> -
</class> -
</hibernate-mapping>
上面在一的一端查询出来的set 里面的记录根据 detetime 的升序来排列，注意：是datetime 不是rdatetime
对于注解形式，可以采用
import javax.persistence.OrderBy;
@OneToMany(cascade = { CascadeType.ALL }, fetch = FetchType.LAZY, mappedBy = "tblStudyType")
@OrderBy("lessonId ASC")
public Set<TblStudyLesson> getTblStudyLessons() {
return this.tblStudyLessons;
}
的方式来配置set的顺序