题目:
Determine whether an integer is a palindrome. Do this without extra space.
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将数字转化为字符串,头尾相互开始比较,直到结束或者匹配不成功。
实现:
class Solution(object): def isPalindrome(self, x): """ :type x: int :rtype: bool """ if x<0: return False x=str(x) for i in range(len(x)//2): if x[i]!=x[len(x)-i+1]: return False return True