1<m<10
#include<iostream>
#include<string.h>
using namespace std;
int a[1000],i;
//10进制转m进制
void _10tom(int m,long long num)
{
//确保数为0时至少执行一次
do
{
a[i++] = num%m;
num /= m;
}while(num!=0);
}
int main(){
int m, A, B;
while (cin >> m >> A >> B)
{
if (m == 0)
return 0;
i = 0;
_10tom(m, A + B);
for (int j = i - 1; j >= 0; j--)
cout << a[j];
cout << endl;
}
return 0;
}