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/**
HDU 6354 E : Everything Has Changed
链接:http://acm.hdu.edu.cn/showproblem.php?pid=6354
题意:求所给图案交的周长;
只考虑内切和相交的情况; 用余弦定理定理可以求解;
*/
#include<bits/stdc++.h>
#define pi acos(-1.0)
using namespace std;
int main(){
int t; cin>>t;
while(t--){
int n;double R;
scanf("%d %lf",&n,&R);
double ans=2*pi*R;
while(n--){
double x,y,r; scanf("%lf %lf %lf",&x,&y,&r);
if(sqrt(x*x+y*y)+r<R||sqrt(x*x+y*y)>=R+r) continue;
else if(sqrt(x*x+y*y)+r==R) ans+=2*pi*r;
else if(sqrt(x*x+y*y)+r>R&&sqrt(x*x+y*y)<(R+r)){
ans+=(2*r*acos((x*x+y*y+r*r-R*R)/(2*sqrt(x*x+y*y)*r)));//内加;
ans-=(2*R*acos((x*x+y*y+R*R-r*r)/(2*R*sqrt(x*x+y*y))));//剩余;
}
}
printf("%.7f\n",ans);
}
return 0;
}