撸点代码,或难或易——1

#include<iostream>
#include<windows.h>
using namespace std;
int main()
{
 cout << "题目:给你一些钱,3元一瓶饮料,每3个瓶盖换一瓶饮料,问能喝几瓶饮料?"<<endl;
 cout << "请输入钱数:" << endl;
 int money_num,cola_num=0;
 cin >> money_num;
 int ping_num, change_num;
 ping_num = money_num / 3;
 cola_num = cola_num + ping_num;
 while(ping_num >= 3)
 {
  change_num = ping_num / 3;
  ping_num = change_num + ping_num - change_num * 3;
  cola_num = cola_num + change_num;
 }
 if (ping_num == 2)
 {
  cola_num = cola_num + 1;
 }
 cout <<"你能喝"<< cola_num <<"饮料!"<< endl;
 system("pause");
}

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转载自blog.csdn.net/Do_or_die_hard/article/details/79027323