原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=6441
代码:
//hoj_6441
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int t,n,a;
long long b,c;
cin>>t;
for(int i=1;i<=t;i++)
{
scanf("%d%d",&n,&a);
if(n>2||n==0)
printf("-1 -1\n");
else if (n==1)
{
printf("1 %d\n",a+1);
}
else if(n==2)
{
if (a%2!=0)//ji
{
b=a*a/2;
c=b+1;
}
else if (a%2==0)//ou
{
if (a%4==0)
{
b=a/4*3;
c=a/4*5;
}
else
{
b=(a/2)*(a/2)-1;
c=((a/2)*(a/2)/2+1)*2;
}
}
printf("%lld %lld\n",b,c);
}
}
return 0;
}