1 select child.id, child.name, count(child.name) depth
2 from category parent, category child
3 where child.left >= parent.left
4 and child.right <= parent.right
5 group by child.name
6 order by child.left;
树形菜单数据结构
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转载自www.cnblogs.com/guanghe/p/9576876.html
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