1.
select count(),B.id,B.channelId,B.name,B.sumorgId from ( select from (select count(*) as sumNum,id,name,orgId as sumorgId from 表名 where 条件 group by name ) as A left join 另一张表名 on A.name = 另一张表名.name where 条件) B group by B.channelId
SELECT count(*),channelcount.parentId,channelcount.channelId,channelcount.channelName,
channelcount.sumorgId FROM
(select * from
(SELECT count(*) AS sumNum, parentId,channelId,channelName,orgId as sumorgId
FROM capturerecord where orgId="ec851ac422dc40ad875cdc86a656d71c"
GROUP BY parentId)as capture left join realexpeople on
capture.parentId =realexpeople.id where realexpeople.id is null) channelcount
GROUP BY channelcount.channelId