#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
using namespace  std;


void input_Row_Column(int a[])
{
	//cout << "请输入两个整数要求大于0且小于1000" << endl;
	char c = ' ';
	int i = 0;
	while ((c = getchar()) != '\n')
	{
		if (c != ' ')//把这句判断条件改动
		{
			ungetc(c, stdin);
			cin >> a[i++];
		}
	}
	//++++需要通过asscii码判断如果不是整数则.......
}



void main()
{

	//1 定义变量 并得到合理区间的T值 [1, 10]
	int T = 0;     //数据数组 T
	vector<string> strs;

	bool TisRight = true;//
	cin >> T;
	while (TisRight)
	{
		if (1 <= T  &  T <= 10)
		{
			TisRight = false;
		}
		else
		{
			cin >> T;
		}
	}
	//cout << T << endl;

	//2 多个矩阵以及对应的行列数
	int N = 0;
	cin >> N;
	//cout << N << endl;
	int row = 0, column = 0;  //矩阵的行和列
	int a[2] = { 0, 0 };
	vector<int> nums;
	vector<vector<int>> allNum;


	for (size_t i = 0; i < T; i++)
	{
		for (size_t j = 0; j < N+1; j++)
		{
			input_Row_Column(a);  //++++bool来提高程序的鲁棒性
			row = a[0];
			column = a[1];
			nums.push_back(row);
			nums.push_back(column);
		}
		nums.erase(nums.begin());
		nums.erase(nums.begin());

  //这儿的思路不对，如果是4对的怎么
		int num = 0;
		if (nums[1] == nums[2] && nums[0] == nums[4] && nums[3] == nums[5])
		{
			strs.push_back("yes");
			//cout << "yes" << endl;
		}
		else
		{
			strs.push_back("no");		
			//cout << "no" << endl;
		}
		nums.clear();
		allNum.clear();
	}
	

	vector<string>::iterator iter;
	iter = strs.begin();
	while (iter != strs.end())
	{
		cout << *iter <<endl;
		iter++;
	}

	//system("pause");

}

随意组合的意思

最后一个结果不对，没想明白？