SELECT feed.FEED_ID,
GROUP_CONCAT(img.IMG_URL ORDER BY img.orders ASC) AS IMG_URL
FROM FEED feed
LEFT JOIN IMG img ON img.FEED_ID=feed.FEED_ID
WHERE feed.FEED_ID='00001'
GROUP_CONCAT函数使用
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转载自xa-zbl.iteye.com/blog/2300614
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