题意是根据输入的姓名和生日信息,比年龄大小,输出最年幼和最年长的人的姓名,各占一行。
题目挺简单的,也就是多熟悉熟悉python,我也就用了土办法,直接比较生日大小,然后做记录。
python版本代码
name = []
n = int(input())
maxp = minp = 0
maxi = mini = 0
for i in range(n):
str,dd,mm,yyyy = input().split()
ymd = int(yyyy)*10000 + int(mm)*100 + int(dd)
name.append(str)
if i == 0:
maxp = minp = ymd
maxi = mini = i
else:
if(ymd > maxp):
maxp = ymd
maxi = i
if(ymd < minp):
minp = ymd
mini = i
print(name[maxi])
print(name[mini])
C/C++版本代码
#include <iostream>
#include<cstdio>
using namespace std;
#define ZANGFONG
char name[101][20];
int main()
{
#ifdef ZANGFONG
freopen("in.txt","r",stdin);
freopen("out.txt","w",stdout);
#endif // ZANGFONG
int i,n,maxp,minp,maxi,mini;
int d,m,y,bd;
scanf("%d\n",&n);
scanf("%s%d%d%d\n",&name[0],&d,&m,&y);
bd = y*10000 + m * 100 + d;
maxp = minp = bd;
maxi = mini = 0;
for(i = 1; i < n; i++)
{
scanf("%s%d%d%d\n",&name[i],&d,&m,&y);
bd = y*10000 + m * 100 + d;
if(maxp > bd)
{
maxp = bd;
maxi = i;
}
if(minp < bd)
{
minp = bd;
mini = i;
}
}
printf("%s\n%s\n",name[mini],name[maxi]);
return 0;
}