JQ 每4位数字出现一次空格

<!DOCTYPE html>
<html lang="zh-cn">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1, user-scalable=no">
<title></title>
<script src="jquery-1.10.1.min.js" ></script>
</head>
<body>
<input type="text" id="alterNumber" style="width: 300px;"/>
<script>
$(function() {
	//难点不是插入空格,而是修正光标的位置,这个只支持IE9+
	//可用于银行卡号
	$('#alterNumber').on('keyup', function(e) {
		//只对输入数字时进行处理
		if((e.which >= 48 && e.which <= 57) || (e.which >= 96 && e.which <= 105 )){
			//获取当前光标的位置
			var caret = this.selectionStart;
			//获取当前的value
			var value = this.value;
			//从左边沿到坐标之间的空格数
			var sp =  (value.slice(0, caret).match(/\s/g) || []).length;
			//去掉所有空格
			var nospace = value.replace(/\s/g, '');
			//重新插入空格
			var curVal = this.value = nospace.replace(/(\d{4})/g, "$1 ").trim();
			//从左边沿到原坐标之间的空格数
			var curSp = (curVal.slice(0, caret).match(/\s/g) || []).length;
			//修正光标位置
			this.selectionEnd = this.selectionStart = caret + curSp - sp;
		}
	})
})
</script>	
</body>
</html>

效果图:

 

参考来源:http://www.cnblogs.com/rubylouvre/p/6087353.html

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转载自onestopweb.iteye.com/blog/2348920
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