java不用系统函数String转int

版权声明:本文为博主原创文章,转载希望能注明出处,感谢。 https://blog.csdn.net/u010126792/article/details/82495069
public class Demo13 {

	public static void main(String[] args) throws Exception {
		String s1 = "-092376";
		String s2 = "-a92376";
		String s3 = "92376";
		String s4 = "923a76";
		System.out.println("s1转换前的str:" + s1);
		System.out.println("s1转换后的int:" + stringtoint(s1));
		System.out.println("s2转换前的str:" + s2);
		System.out.println("s2转换后的int:" + stringtoint(s2));
		System.out.println("s3转换前的str:" + s3);
		System.out.println("s3转换后的int:" + stringtoint(s3));
		System.out.println("s4转换前的str:" + s4);
		System.out.println("s4转换后的int:" + stringtoint(s4));

	}

	/**
	 * 不用内置转换函数把String转换成int -1 代表转换失败
	 * 
	 * @param strnum
	 * @return
	 */
	public static int stringtoint(String strnum) {
		int number = 0;
		char navigaTag = '-';
		boolean isNavigate = false;
		if (strnum == null || strnum.length() == 0) {
			return -1;
		}
		// char[] straar = strnum.toCharArray();
		for (int i = 0; i < strnum.length(); i++) {
			if (i == 0) {
				if (strnum.charAt(0) == navigaTag) {
					isNavigate = true;
					continue;
				}
			}

			char sinChar = strnum.charAt(i);
			if (sinChar > '9' || sinChar < '0') {
				return -1;
			}
			number = number * 10;// 每次*10添加到个位

			// 会转换成ASCII码对应的十进制值进行运算,'9'-'0'= 9
			number += strnum.charAt(i) - '0';

		}

		return isNavigate ? number * -1 : number;
	}

}

猜你喜欢

转载自blog.csdn.net/u010126792/article/details/82495069