Validate if a given string is numeric.

Some examples:
"0" => true
" 0.1 " => true
"abc" => false
"1 a" => false
"2e10" => true

Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.

想要ac这个问题真的是要历经千辛万苦，不断的根据评测结果修改自己的条件代码，最终才能符合要求。

以下是leetcode大神ac的c++代码，格式条例清晰，供给学习。

class Solution {
public:
    bool isNumber(string str) {
        int state=0, flag=0; // flag to judge the special case "."
        while(str[0]==' ')  str.erase(0,1);//delete the  prefix whitespace 
        while(str[str.length()-1]==' ') str.erase(str.length()-1, 1);//delete the suffix whitespace
        for(int i=0; i<str.length(); i++){
            if('0'<=str[i] && str[i]<='9'){
                flag=1;
                if(state<=2) state=2;
                else state=(state<=5)?5:7;
            }
            else if('+'==str[i] || '-'==str[i]){
                if(state==0 || state==3) state++;
                else return false;
            }
            else if('.'==str[i]){
                if(state<=2) state=6;
                else return false;
            }
            else if('e'==str[i]){
                if(flag&&(state==2 || state==6 || state==7)) state=3;
                else return false;
            }
            else return false;
        }
        return (state==2 || state==5 || (flag&&state==6) || state==7);
    }
};