版权声明：本文为博主原创文章，转载请注明出处。 https://blog.csdn.net/qq_18860653/article/details/83109774
当我们想遍历一个节点下的所有子节点的时候，我们可以借助jQuery - each() 方法这么做
<html lang="zh">
<head>
<title>[html常用脚本整理]</title>
<meta charset="UTF-8" />
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.js"></script>
</head>
<body>
<ul id='my-ul'>
<li data-key='1'>111</li>
<li data-key='2'>222</li>
<li data-key='3'>333</li>
<li data-key='4'>444</li>
<li data-key='5'>555</li>
</ul>
<button onclick="doClick()">点击</button>
</body>
<script>
function doClick(){
var myUl = $("#my-ul").find("li");
myUl.each(function(index,e){
console.log(index+' '+$(e).html())
})
}
</script>
</html>