#include <iostream>
using std::cout;
using std::endl;
#define CNT( a ) sizeof(a)/sizeof(*a)
template<typename T>
int fCNT( T* a )
{
int nCnt = 0;
T* p = a;
while ( 0 != *p++ )
nCnt++;
return nCnt+1;
}
int main()
{
//char a[] = "abcdef";
char a[8] = {0}; // int char a[8] = {0};
for ( int i = 0; i < 7; i++ )
a[i] = 97+i;
cout << "CNT(a): " << CNT(a) << endl;
cout << "fCNT(a): " << fCNT(a) << endl;
return 0;
}
这种方法有个限制条件:数组需要初始化为0。
至于针对于general 的数组,暂时没有想出更好的解决方法。