Problem A: Person类与Student类的关系

Time Limit: 1 Sec Memory Limit: 128 MB
Submit: 1403 Solved: 1056
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Description

当然，一个student首先是一个person。所以，Student类是Person类的派生类。请定义Person类，包括：

1. 数据成员string name和int age，分别表示姓名和年龄。

2. 构造函数和析构函数，它们有相应的输出，见样例。

3. void show()函数：按照样例输出该对象的name和age属性值。

定义Student类，是Person类的子类：

1. 数据成员int grade，表示学生所在年级。

2. 构造函数和析构函数，它们有相应的输出，见样例。

3. void show()函数：按照样例输出该对象的grade属性值。

Input

只有1行，分为三部分：一个不含空白符的字符串以及两个整数。

Output

见样例。

Sample Input

Tom 19 3

Sample Output

A person Tom whose age is 19 is created.
A student whose grade is 3 is created. Name is Tom and age is 19.
Grade is 3.
A student whose grade is 3 is erased. A person Tom whose age is 19 is erased.

Append Code

int main()
{
    string n;
    int a, g;
    cin>>n>>a>>g;
    Student student(n, a, g);
    student.Person::show();
    student.show();
    return 0;
}

#include <iostream>
#include <string>
using namespace std;

class Person
{
private:
    string name;
    int age;
public:
    Person(string n,int a):name(n),age(a){cout<<"A person "<<name<<" whose age is "<<age<<" is created."<<endl;}
    ~Person(){cout<<"A person "<<name<<" whose age is "<<age<<" is erased."<<endl;}
    void show(){cout<<"Name is "<<name<<" and age is "<<age<<"."<<endl;}

};

class Student:public Person
{
public:
    Student(string n,int a,int g):Person(n,a){
        grade = g;
        cout<<"A student whose grade is "<<grade<<" is created."<<endl;}
    ~Student(){cout<<"A student whose grade is "<<grade<<" is erased."<<endl;}
    void show(){cout<<"Grade is "<<grade<<"."<<endl;}
private:
    int grade;
};

int main()
{
    string n;
    int a, g;
    cin>>n>>a>>g;
    Student student(n, a, g);
    student.Person::show();
    student.show();
    return 0;
}